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Classnotes 14
Final States
Stars evolve from the main sequence to their deaths. For single
stars, there are three possible final states:
Objects with M 0.08M
are not stars: they do not burn H to He. They approach the main
sequence, fail to ignite H, and cool and fade slowly. They do
not continue to collapse because they are supported by the pressure
of degenerate electrons.
Objects with masses between 0.08 and 0.8 M burn
H to He and must eventually exhaust their supply of H. But even
a 0.8M star remains on the main sequence for an age
greater than the age of the Universe.
White dwarfs and neutron stars are Final States in the sense
that gravity's desire to squash a star is permanently and finally
thwarted by a pressure that does not depend on temperature.
This is the pressure of degenerate electrons (white dwarfs) or
degenerate neutrons (neutron stars). WD and NS cool, and fade
but do not collapse further. A WD has a radius about that of
the Earth. A NS has a radius of about 10 km (the size of Austin).
Degenerate electrons provide a limited
pressure. The mass of a WD cannot exceed 1.4 M ), a limit
known as Chandrasekhar's mass. The mass of a NS cannot exceed
about 2 to 3 M (the actual value is uncertain)
owing to the maximum pressure provided by degenerate neutrons.
Above 2 to 3 M ), the stellar remnant continues
to collapse. This is a Black Hole.
Degenerate electrons also play a part in the evolution of stars
prior to their attaining their final states. Seeds offers a brief
introduction (Box 10- 1) to degenerate matter. Here is a more
complete account.
Degenerate Electrons and Neutrons
Two fundamental and secure principles of physics govern the behavior
of a gas at very high densities.
Consider a gas composed of electrons. We may say that an electron
requires a minimum volume to call its own. This volume is defined
by the Heisenberg Uncertainty Principle, see Appendix.
As I shall consider a one-dimensional gas, I state this principle
in that form: where is the smallest length to which an electron can be
confined and is the smallest increment in momentum (energy, for
our purposes) that can be given an electron. is a constant
(a small number).
The second principle is the Pauli Exclusion Principle.
This states that no more than 2 electrons can have the same energy
and position. "Same" means within and of each other.
The restriction to 2 is related to the spin of the electron.
The electron may spin 'up' or 'down' and the 2 electrons in the
same 'box' must have opposite spin.
Consider now an 1D example. We can locate each electron on a
momentum (energy) - position diagram. The squares are by in size. No square
may contain more than 2 electrons.
Normal (non-degenerate) Gas
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--We note many empty boxes among the lowest
energy boxes.
--All filled boxes are at the lowest energys.
--Electrons can move pretty freely to left
and right without coming up agains the 2 per box limit.
--Electrons can collide and exchange energy
as empty boxes are available.
--We can compress the gas; i.e.,
take the 11 boxes in the first diagram and squeeze it down to
seven boxes; some boxes will still not have their full quota
of 2.
--This gas can lose energy out through
the sides -- higher energy electrons can fine a home in a lower
energy box after transferring some energy to the outside.
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--And this obeys all other
laws applicable to normal gases.
A Degenerate Gas
At high densities, the boxes fill up. We
then say the electrons are degenerate. In the same 1-dimensional
picture, this would be like
-- All low energy boxes (states) are filled.
-- Further compression requires that higher
energy states be filled.
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This Requires Hard Work!!
--Low energy electrons cannot exchange
energy easily because the adjacent boxes are filled.
--The mobile electrons are those at the
highest energies and the highest velocity and these gain energy
easily but not lose very much.
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This property explains why metals are good
conductors of heat (energy) and electricity (electrons carry
charge.)
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--The pressure that a degenerate electron
gas can exert is a permanent pressure. This high energy electrons
cannot lose their energy because all the lower energy boxes are
filled.
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Contrast this with a normal gas:
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So, a degenerate electron gas can permanently
withstand the self-gravitation -- its energy cannot be
radiated away.
Examples include,
-white dwarfs -- they cool off but never
collapse to zero,
-black dwarfs -- either low mass stars
(brown dwarfs) that never ignited H or exhausted white dwarfs,
-cores of low mass red giants.
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Can gravitation ever win when the
electrons try the degenerate 'trick'?
Yes! Einstein - special relativity - says velocity cannot exceed
the speed of light (c), i.e., there is an energy ceiling and
hence, an upper limit to the pressure provided by degenerate
electrons. If gravity exceeds this pressure, the star will collapse
in spite of the degenerate electrons. Chandrasekhar showed that
this ceiling was reached with a degenerate star with a mass of
1.44 M - now known as Chandrasekhar's Limit
(exact numerical value depends on the type of nuclei mixed in
within the electrons). This is the limit for helium (why do we
choose He and not hydrogen?).
The nuclei generally escape the box filling
problem because their boxes are much smaller. (Also, one He nucleus
is matched by 2 electrons so nuclei are less numerous).
Neutron Stars
For stellar cores above 1.44 M , collapse is not
halted by the degenerate electrons. Also for lower masses, it
may be possible to achieve more squashing; for example, the core
may be part of a more massive star.
There can come a time when electrons and nuclei (positively charged,
of course) are forced so close that they can cancel out their
charges.
For example:
(At these high densities, the He nuclei produced in an earlier
stage of nuclear burning of H are broken down into protons and
neutrons). Then the core becomes a neutron star.
At normal densities, neutrons are unstable
and decay n --> p + e-+ v in a little over 11
minutes. At these high densities, neutron formation dominates
over decay.

But neutrons obey a form of the Pauli Neutrino principle too,
so we can (and do) have a degenerate neutron gas and a mass limit
equivalent to Chandrasekhar's. Actually, the limit is set by
the fact that neutrons can be broken down into even more elementary
particles: this is likely to occur as the high energy neutrons
near the top of the neutron sea collide and fragment. Here, the
physicist is on a frontier of his/her knowledge and opinions
vary, but MNeutron Star < 3 M is a
best guess.
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The figure shows what a neutron star is
thought to look like. Note three things:
| 1. |
The radius of
the star is small (10km). |
| 2. |
The crust contains
nuclei. Neutrons exist below the crust. |
| 3. |
The ? in the
center. These mean no one really knows what goes on there. Quarks
are the elementary particles that make up neutron and protons. |
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Nuclear Reactions in Degenerate Electron
Gas
In a star, the energy input comes from nuclear reactions. Consider
now the ignition of He in a low mass red giant. He burning starts
and the core is heated. The core does not expand because it is
(electron) degenerate. Nuclei are not degenerate - they continue
to heat up and reat faster and not degenerate. For example, in
the interior of main sequence stars, injection of heat causes
the gas (electrons and nuclei) to
expand. Expansion lowers the density and temperature and the
release of nuclear energy from 4H --> He is slowed.
1. Degenerate electron gas (and associated nuclei) cannot expand
and cool when energy is put in.
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- 2. Inside star, electrons are degenerate,
but the atomic nuclei are not. Energy input comes from nuclear
reactions (collisions between nuclei).
3. Energy input from reactions has no effect on electrons,
but nuclei respond by moving faster.
4. When nuclei move faster, there are more nuclear reactions.
5. Therefore, more energy is put into the gas and the nuclei
move faster still.
-
- 6. More nuclear reactions --> more
energy into gas --> nuclei move faster --> more nuclear
reactions.
7. Eventually, sufficient energy is given to the electrons to
"lift" their degeneracy.
This is an example of a runaway process.
This example leads to an explosion. If the explosion occurs in
the core of a star, the outer cooler layers may contain the explosion
and prevent the star from blowing itself apart.
Appendix
Discussions of the uncertainty principle are often put in the
form of presenting a duffer (and long live all such duffers)
who attempts to do an experiment which will deny the predictions
of the principle; he retires, of course, bruised from the ring.
Heisenberg, whose principle this is, presented such a duffer
in order to show that all such gedanken experiments (thought
experiments) must fail. His jester used a microscope to measure
the position of the particle and, in order to do so with increasing
precision, selected one operating with ever shortening wavelength
of light. But the shorter the wavelength the more momentum each
photon carries and since at least one photon must be scattered
into the microscope aperture in order for the position to be
determined, it is clear that the very act of observation imparts
a momentum to the particle. An analysis of the experiment, taking
into account aperture-diffraction effects and momentum transfers
on light scattering, concludes that the uncertainty product
is indeed not less than .-In a classical world the jester would
laugh last, because would be zero and there would be no intrinsic
limitation on the precision.
Syllabus | Classnotes 2 | Classnotes
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Classnotes
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